Find the average value of the function $f(x) = 2x^2$ on the interval $0 \le x \le 2$
Added by Ronald H.
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The definite integral of a constant function is equal to the value of the constant multiplied by the width of the interval. In this case, the width of the interval is 2 - 0 = 2. So, the definite integral of f(x) = 2 over the interval [0,2] is: ∫[0,2] 2 dx = 2x Show more…
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