2x}$, a = 0, and b = 4
Now, we need to find the integral of f(x) from 0 to 4:
$\int_0^4 10e^{-0.2x}dx$
To solve this integral, we can use substitution. Let u = -0.2x, so du = -0.2dx. Then, dx = $\frac{du}{-0.2}$.
Now, we can rewrite the integral in terms of
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