Find the average value over the given interval. 32) y = 5 x2; [-1,2]
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So, we have: Average Value = $\frac{1}{2 - (-1)} \int_{-1}^2 5x^2 dx$ Now, we need to find the integral of 5x^2: $\int 5x^2 dx = \frac{5}{3}x^3 + C$ Now, we can plug in the limits of integration: Show more…
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