'Find the area between y = e" and y = e2x over [0, 1].'
Added by Nathaniel H.
Step 1
To find the intersection points, we set y = e^x and y = e^(2x) equal to each other: e^x = e^(2x) Taking the natural logarithm of both sides, we get: x = ln(2) So the two curves intersect at the point (ln(2), e^ln(2)) = (ln(2), 2). Show more…
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