Find the absolute minimum value of the function g(x) = (e^x)/x, x > 0
Added by Joseph M.
Step 1
To do this, we take the derivative of g(x) with respect to x: g'(x) = (xe^x - e^x)/x^2 Setting g'(x) equal to zero, we get: xe^x - e^x = 0 e^x(x-1) = 0 So the critical points are x=0 and x=1. Show more…
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