Question

Formula $I = \frac{V}{R}$ $230 V$ $: I = \frac{230 V}{1000 \Omega} = 0.23 A.$ $: The current flowing through the filament of the bulb = 0.23 A. Example 2 : The length of a conducting wire is 50 cm and its radius is 0.5 mm. If its resistance is 30 $\Omega$, what is the resistivity of its material? Given : L = 50 cm = 50 × $10^{-2}$ m

          Formula  $I = \frac{V}{R}$ 
$230 V$
$: I = \frac{230 V}{1000 \Omega} = 0.23 A.$
$: The current flowing through the filament
of the bulb = 0.23 A.
Example 2 : The length of a conducting
wire is 50 cm and its radius is 0.5 mm. If its
resistance is 30 $\Omega$, what is the resistivity of
its material?
Given : L = 50 cm = 50 × $10^{-2}$ m

Show more…

Formula I = (V)/(R)
230 V
: I = (230 V)/(1000 Ω) = 0.23 A.
: The current flowing through the filament
of the bulb = 0.23 A.
Example 2 : The length of a conducting
wire is 50 cm and its radius is 0.5 mm. If its
resistance is 30Ω, what is the resistivity of
its material?
Given : L = 50 cm = 50 ×10^-2m

Added by Robert G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Shyam P

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First, we need to know the material of the object. Different materials have different resistivities. Show more…

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