Question

Q.11 The potential energy U of a particle varies with distance x from origin as $U = \frac{\alpha x^{3/2}}{\beta + x}$, where $\alpha$ and $\beta$ are dimensional constants, then dimensional formula of $[\frac{\alpha}{\beta}]$ is Choose answer: $[ML^{1/2}T^{-2}]$ $[M^0L^0T^{-2}]$ $[ML^{7/2}T^{-2}]$ $[ML^{3/2}T^{-2}]$

          Q.11
The potential energy U of a particle varies with distance x
from origin as $U = \frac{\alpha x^{3/2}}{\beta + x}$, where $\alpha$ and $\beta$ are dimensional
constants, then dimensional formula of $[\frac{\alpha}{\beta}]$ is
Choose answer:
$[ML^{1/2}T^{-2}]$
$[M^0L^0T^{-2}]$
$[ML^{7/2}T^{-2}]$
$[ML^{3/2}T^{-2}]$

Show more…

Q.11
The potential energy U of a particle varies with distance x
from origin as U = (α x^3/2)/(β + x), where α and β are dimensional
constants, then dimensional formula of [(α)/(β)] is
Choose answer:
[ML^1/2T^-2]
[M^0L^0T^-2]
[ML^7/2T^-2]
[ML^3/2T^-2]

Added by Valerie R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Nishant Kumar

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