Find $\frac{\partial z}{\partial x}$ if $z = 6x^3 + 4x^2y + 9y^3$. $\frac{\partial z}{\partial x} = $
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The partial derivative of z with respect to x is: \(\frac{\partial z}{\partial x} = 18x^2 Axy + 6Ax^2\) The partial derivative of z with respect to y is: \(\frac{\partial z}{\partial y} = 6Ax^2 + 9\) Now, we need to find the second partial derivatives. Show moreβ¦
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