Find f (0 1 '4 g(x) = x2 , { +
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Since g(x) = x^2, its derivative g'(x) is: g'(x) = 2x Now, we are given that f(0) = 1. We also know that f'(x) = 4g(x). So, we can write the differential equation for f(x) as: f'(x) = 4g(x) Now, we can substitute g(x) = x^2 into the equation: f'(x) = 4x^2 Show more…
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