Find dw. If W=2x} + 3x? y ~ 8y2
Added by Joseph L.
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For x: $$ \frac{\partial W}{\partial x} = \frac{\partial}{\partial x}(2x^3 + 3x^2y - 8y^2) = 6x^2 + 6xy $$ For y: $$ \frac{\partial W}{\partial y} = \frac{\partial}{\partial y}(2x^3 + 3x^2y - 8y^2) = 3x^2 - 16y $$ Now, we need to find the differential of W, Show more…
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