Using the product rule, we have:
$$\frac{d y}{d x} = \frac{d}{d x} (x(x-2)(x+1))$$
Expanding the product, we get:
$$\frac{d y}{d x} = \frac{d}{d x} (x^3 - x^2 - 2x^2 + 2x)$$
Simplifying, we get:
$$\frac{d y}{d x} = \frac{d}{d x} (x^3 - 3x^2 + 2x)$$
Taking the
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