Find (int_{0}^{sqrt{frac{5pi}{3}}} int_{0}^{sqrt{frac{pi}{6}}} xy sin(x^2 + y^2) dx dy)
Added by Fernando C.
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The function is: $$c\sin(z^2 + y^2)$$ Now, we will find the partial derivative with respect to y: $$\frac{\partial}{\partial y}(c\sin(z^2 + y^2))$$ Using the chain rule, we get: $$c\cos(z^2 + y^2) \cdot \frac{\partial}{\partial y}(z^2 + y^2)$$ Show more…
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