Find a particular solution to y'' + 5y' + 6y = 20te^(2t)
Added by Magdalena B.
Step 1
The characteristic equation is r^2 + 5r + 6 = 0, which factors as (r+2)(r+3) = 0. Therefore, the homogeneous solution is y_h(t) = c1e^(-2t) + c2e^(-3t). Show more…
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