Find a general solution to the differential equation: u'' - 2u' + u = (e^s)/s.
Added by Janet B.
Step 1
The characteristic equation is: r^2 - 2r + 1 = 0 This can be factored as (r-1)^2 = 0, so the roots are r=1 (with multiplicity 2). Therefore, the homogeneous solution is: u_h(t) = c_1 e^t + c_2 t e^t where c_1 and c_2 are constants determined by the initial Show more…
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