Find a general solution of y' = (2+2i13)y: y(x)
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First, we need to find the characteristic equation of the differential equation: r^2 + (2+2i13) = 0 Using the quadratic formula, we get: r = (-2-2i13 ± sqrt((2+2i13)^2 - 4(1)(2+2i13)))/2 r = (-1-i13 ± sqrt(-52i))/2 Since the square root of a negative number is Show more…
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