Question

Find 4A + 2B. $A = \begin{bmatrix} 6 & 8\\ 7 & 6 \end{bmatrix}$ $B = \begin{bmatrix} -3 & 4\\ 1 & -1 \end{bmatrix}$ $4A + 2B = \begin{bmatrix} \Box & \Box\\ \Box & \Box \end{bmatrix}$

          Find 4A + 2B.
$A = \begin{bmatrix} 6 & 8\\ 7 & 6 \end{bmatrix}$ 
$B = \begin{bmatrix} -3 & 4\\ 1 & -1 \end{bmatrix}$
$4A + 2B = \begin{bmatrix} \Box & \Box\\ \Box & \Box \end{bmatrix}$

Find 4A + 2B.
A =
< b m a t r i x >
B =
< b m a t r i x >
4A + 2B =
< b m a t r i x >

Added by Melanie R.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Gaurav Gupta

Step 1

A = 76/6 = 38/3 B = -3 So, 4A + 2B = 4(38/3) + 2(-3) = 152/3 - 6 = 140/3 Show more…

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Find 4A + 2B. 6]8 A = 7 6 -3 B=| 4A + 2B =

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Question

Find 4A + 2B. $A = \begin{bmatrix} 6 & 8\\ 7 & 6 \end{bmatrix}$ $B = \begin{bmatrix} -3 & 4\\ 1 & -1 \end{bmatrix}$ $4A + 2B = \begin{bmatrix} \Box & \Box\\ \Box & \Box \end{bmatrix}$

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