Factor each polynomial completely. $$ 6 w^{3} z+6 z $$
Added by Gina P.
Step 1
$$ 6w^3z + 6z = 6z(w^3 + 1) $$ Now, we can use the sum of cubes formula, which states that $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$. In this case, $a = w$ and $b = 1$. Show more…
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