(e^x + 1)^2e^-y + (e^x + 1)^3e^-x frac{dy}{dx} = 0
Added by James L.
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Step 1
Let's substitute: u = ey + 1, v = ex + 1 Then, we have: du = e^y dy, dv = e^x dx Now, we can rewrite the equation in terms of u and v: Show more…
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