Express sin 6θ as a polynomial in sin θ and cos θ.
Added by Nancy F.
Step 1
We can use the identity for the sine of a double angle: sin 2θ = 2 sin θ cos θ We can apply this identity twice to get: sin 4θ = 2 sin 2θ cos 2θ = 2 (2 sin θ cos θ) (cos^2 θ - sin^2 θ) = 4 sin θ cos^3 θ - 4 sin^3 θ cos θ Now we can use the identity for the sine Show more…
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