Evaluate the integrals using integration by parts. $$ \int e^{-2 x} \sin 2 x d x $$
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Let's choose: u = sin 2x dv = e^(-2x) dx Then, we can find du and v: du/dx = 2 cos 2x v = -1/2 e^(-2x) Now, we can use the integration by parts formula: ∫ u dv = u v - ∫ v du Plugging in our values, we get: ∫ e^(-2x) sin 2x dx = -1/2 e^(-2x) sin 2x - ∫ Show more…
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