Evaluate the integrals. $$\int \frac{e^{-1 / x^{2}}}{x^{3}} d x$$
Added by Jason T.
Step 1
Substituting this into the integral, we get: $$\int \frac{e^{-1/x^2}}{x^3} dx = -\frac{1}{2} \int u^{-\frac{3}{2}} e^{-u} du$$ Show more…
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