'Evaluate the integral: V 3/2 5 dt V1 -t2'
Added by Justin F.
Step 1
First, we need to find the antiderivative of the integrand, which is: ∫(1-t^2)^(-1/2) dt We can use the substitution u = 1-t^2, du = -2t dt, to rewrite the integral as: -1/2 ∫u^(-1/2) du = -u^(1/2) + C where C is the constant of integration. Show more…
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