$$
\int \frac{3}{x^3} dx = 3 \int x^{-3} dx
$$
Now, we can use the power rule for integration:
$$
\int x^n dx = \frac{x^{n+1}}{n+1} + C
$$
So, for our integral, we have:
$$
3 \int x^{-3} dx = 3 \frac{x^{-2}}{-2} + C = -\frac{3}{2x^2} + C
$$
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