Evaluate the integral.\\ $\int \sin^{5} (7x) \, dx$
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The power reduction formula for sine is: sin^n(x) = (1/2^n-1) * Σ(k=0 to n) (-1)^k * (n choose k) * sin(x + (n-2k)π/2) Applying this formula to sin^5(7x), we get: sin^5(7x) = (1/16) * [sin(7x) - 10sin(3x) + 5sin(x)] Show more…
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