The integral should be:
$$\int f z r \sin(Tr) dr$$
Now, we can integrate with respect to $r$:
$$\int f z r \sin(Tr) dr = f z \int r \sin(Tr) dr$$
To solve this integral, we can use integration by parts. Let $u = r$ and $dv = \sin(Tr) dr$. Then, $du = dr$ and
Show more…