Evaluate the expression. $$\log _{2} 6-\log _{2} 15+\log _{2} 20$$
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Step 1
First, we can simplify the expression by using the properties of logarithms: $$\log _{2} 6-\log _{2} 15+\log _{2} 20 = \log _{2} \frac{6 \cdot 20}{15}$$ Show more…
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