Evaluate the definite integral: f8 dx 22+9
Added by Seth W.
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We can do this by using u-substitution. Let u = 22+9x, then du/dx = 9 and dx = du/9. Substituting these into the integral, we get: ∫ 8/(22+9x) dx = ∫ 8/u * (1/9) du = (8/9) ln|22+9x| + C where C is the constant of integration. Show more…
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