Evaluate each sum. $$\sum_{x=6}^{8}(5 x-1)^{2}+\sum_{x=6}^{8}(10 x-1)$$
Added by Nancy E.
Step 1
Step 1:** Expand the first sum: $$(5 \times 6 - 1)^2 + (5 \times 7 - 1)^2 + (5 \times 8 - 1)^2$$ $$= (30 - 1)^2 + (35 - 1)^2 + (40 - 1)^2$$ $$= 29^2 + 34^2 + 39^2$$ ** Show more…
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