Evaluate $\int 2x^2 \ln(3x)dx$ by using integration by parts
Added by Juan B.
Close
Step 1
Let's choose u = √(3x) and dv = 2x dx. Differentiating u, we get du/dx = (1/2)(3x)^(-1/2) * 3 = (3/2√(3x)). Integrating dv, we get v = ∫(2x) dx = x^2. Now, we can use the integration by parts formula: ∫(2x√(3x)) dx = uv - ∫v du Plugging in the values, we Show more…
Show all steps
Your feedback will help us improve your experience
Nicole Hoffman and 69 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the following integral: (2x 3) dx
Madhur L.
Evaluate the integral. $ \displaystyle \int \frac{2x - 3}{x^3 + 3x}\ dx $
Techniques of Integration
Strategy for Integration
Evaluate the integral using integration by parts. ∫2x e^(3x) dx ∫2x e^(3x) dx =
Sri K.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD