Establish the identity.\\ $\sin\left(\frac{3\pi}{2} + \theta\right) = -\cos\theta$
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First, we can simplify the expression by using the double angle formula for cosine: 2cos^2(x/2) - 1 = cos(x) So, we have: 3n sin(40) | 2cos(2x) = 3n sin(40) | 2cos^2(x) - 1 Show more…
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Derive the given identity by using the identities in Exercises $38-40$. $\cos (\theta)-\cos (\phi)=-2 \sin \left(\frac{\theta+\phi}{2}\right) \sin \left(\frac{\theta-\phi}{2}\right)$
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