Equation d1 + 6dx + 24x = 0 when x(0) = 1 and x'(0) = 0 by using the Laplace transform method.
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Now, we can simplify the above equation by substituting the initial conditions: s^2Y(s) - s - 1 + 6sY(s) - 6 + 24Y(s) = 0 Solving for Y(s), we get: Y(s) = (s+1)/(s^2 + 6s + 24) Now, we need to find the inverse Laplace transform of Y(s) to get the solution Show more…
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