00:01
The question is asking us to draw the mo diagram of, which is molecular orbital diagram of carbon.
00:16
Let us look into it.
00:20
First of all, let us understand what is m.
00:23
Mo is a qualitative description for explaining the chemical bonding talks about na and nb, which is number of anti -bondent.
00:39
Electrons or anti -bonding molecular orbitals and number of bonding molecular orbitals.
00:47
For co2 plus, the ec, which is electronic configuration will be one less, one electron less than c2.
01:00
Thus, the electronic configuration, it will be equal to sigma 1 s2.
01:11
Sigma anti -bonding 1 s2 sigma 2 s2 sigma anti -bonding 2 s2 apart from that pi 2px 2 it is is equal to pi anti -bonding 2i by 1 now let us draw the m 2p and 2p it has 3 or there are let us label it first of all, let us look into the base, the ground level atomic orbital, which is over here there will be two electron and in this also there will be two electrons.
01:55
So it will be distributed well.
01:59
In 2s also we can see there are two electrons here also.
02:03
First of all we will be filling up the bonding molecular orbital then the rest will be in empty bonding...