X(t) = \begin{bmatrix} e^{2t} + e^{-4t} \\ e^{2t} - e^{-4t} \end{bmatrix}. \text{Find a planar linear system } X' = AX \text{ to which } X(t) \text{ is a solution.}
Added by Patricia G.
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We have: X'(t) = (d/dt)(e2t + e-4t - e2t e-At) Show more…
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