The inverse Laplace transform of $F(s) = \frac{e^{-6s}}{s^2 + 0s - 25}$ is $f(t) =$ Use $step(t-c)$ for $u_c(t)$
Added by Bianca C.
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This means that f(t) is equal to e raised to the power of -6g. Show more…
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