e" 2 n=1 T" divergent T -e nIn( 2 ) T -e 9 8
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The first series is "2^n / n". We can use the ratio test to determine its convergence: lim(n->inf) |(2^(n+1) / (n+1)) / (2^n / n)| = lim(n->inf) |2n / (n+1)| = 2 Since the limit is greater than 1, the series diverges. Show more…
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