Question

Find $\frac{dy}{dx}$. $y = \frac{5}{4} \sqrt{\frac{8x}{4x - 3}}$ $\frac{dy}{dx} = \square$

          Find $\frac{dy}{dx}$.
$y = \frac{5}{4} \sqrt{\frac{8x}{4x - 3}}$
$\frac{dy}{dx} = \square$

Find (dy)/(dx).
y = (5)/(4)√((8x)/(4x - 3))
(dy)/(dx) = □

Added by Katie W.

Calculus: Early Transcendentals

James Stewart 8th Edition

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