Differentiate the given function. y = x√(8x - 1) y' = (8x - 1)^(1/2) + x * (1/2) * (8x - 1)^(-1/2)
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First, we use the power rule of differentiation to differentiate the term "x V8x": y' = (8x^(7/2))/2 + 1 y' = 4x^(7/2) + 1 Show more…
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