Differentiate the function. \begin{equation*} g(x) = \frac{1}{(3x^3 + 5x + 1)^{3/4}} \end{equation*} \begin{equation*} g'(x) = \end{equation*}
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The derivative of 3x^3 with respect to x is 9x^2. The derivative of Sx with respect to x is S. The derivative of 1 with respect to x is 0. So, the derivative of g(x) is 9x^2 + S. Show more…
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