Differentiate the function. $$ g(t)=\ln \frac{t\left(t^{2}+1\right)^{4}}{\sqrt[3]{2 t-1}} $$
Added by Tonya B.
Step 1
First, we can simplify the expression inside the logarithm using the properties of logarithms: $$ \begin{aligned} g(t) &= \ln \frac{t\left(t^{2}+1ight)^{4}}{\sqrt[3]{2 t-1}} \\ &= \ln t + \ln \left(t^{2}+1ight\right)^{4} - \ln \sqrt[3]{2 t-1} \\ &= \ln t + 4 \ln Show more…
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