f(x) = 8 - x^e^x / x + e^x f '(x) =
Added by Andrew B.
Step 1
Using the quotient rule, we have: f '(x) = [(x + ex)(-ex) - (8 - x^ex)(1 + ex)] / (x + ex)^2 Simplifying this expression, we get: f '(x) = [-xex - ex^2 + 8 + x^ex + 8ex - x^exex] / (x + ex)^2 Combining like terms, we have: f '(x) = [8 + (7ex - xex - ex^2 - Show more…
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