Solve the ODE: dx/dt + 2x = 10e^(-2t), x(0) = 0.
Added by Edward F.
Step 1
Multiplying both sides of the ODE by the integrating factor, we get: e^(2t)dx/dt + 2xe^(2t) = 10 Now, we can recognize the left-hand side as the product rule of (xe^(2t)), so we can rewrite the equation as: d/dt(xe^(2t)) = 10 Integrating both sides with Show more…
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