$\begin{bmatrix} 1 \ 0 \ 1 \end{bmatrix} = (0)u \text{with } u = \begin{bmatrix} 4 & 0 & 0 \ 9 & 3 & 0 \ 1 & 2 & 1 \end{bmatrix} = \frac{up}{np}$
Added by Charles S.
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Step 1
First, we need to find the eigenvalues of the matrix 8 6. To do this, we solve the characteristic equation: det(8 - λ 6) = (8 - λ)(6) - (0)(0 - λ) = 48 - 14λ + λ^2 = (λ - 6)(λ - 8) Therefore, the eigenvalues are λ1 = 6 and λ2 = 8. Show more…
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