Determine where the function $f(x)$ is continuous. $f(x) = \sqrt[3]{10 - x}$ The function is continuous on the interval $oxed{}$ . (Simplify your answer. Type your answer in interval notation.)
Added by Christopher P.
Close
Step 1
The function f(x) = √(1 - x) is defined for all real numbers x such that 1 - x ≥ 0. This means that the function is defined for x ≤ 1. Now, let's consider any potential points of discontinuity. The function f(x) involves taking the square root of (1 - x), which Show more…
Show all steps
Your feedback will help us improve your experience
Chittaranjan Sahoo and 71 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the largest interval over which the given function is continuous. $$ f(x)=\frac{x^{2}-100}{x-10}, c=10 $$
Limits
Continuity of Functions
Determine the intervals on which the following function is continuous. f(x) = (x^2 - 8x + 15) / (x^2 - 9) On what interval(s) is f continuous? (Simplify your answer. Type your answer in interval notation. Use a comma to separate
Adi S.
Check the line if the function is continuous on the given interval. Pay attention to the interval symbols!! (-10, -1) (-10, 1] [-1, 0) (0, 5) (1, 5) [5, 8) Identify a value of x, -10 < x < 10, for which the function is continuous from the right. Identify each value of x, -10 < x < 10, for which the function is not continuous. State the type of discontinuity.
Gregory H.
Recommended Textbooks
Precalculus with Limits
Precalculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD