Determine the limit at infinity: lim x2 + Sx+ 5 X4 x _ 3x2 + 14 1 0 C 0
Added by Lauren T.
Close
Step 1
In this case, it's $x^4$. $\lim_{x\to\infty} \frac{x^2 + 5x + 5}{x^4 - 3x^2 + 14} = \lim_{x\to\infty} \frac{x^4\left(\frac{1}{x^2} + \frac{5}{x^3} + \frac{5}{x^4}\right)}{x^4\left(1 - \frac{3}{x^2} + \frac{14}{x^4}\right)}$ Now, we can cancel out the $x^4$ Show more…
Show all steps
Your feedback will help us improve your experience
Hemraj Kumawat and 97 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the following limits: a) lim x → ∞ [(5x^2 + 7)/(3x + 2x^2)] b) lim x → ∞ [(3x + 1)/(x^3 + 2x^2 + 4)] c) lim x → ∞ [(-4x^3 + x^5 + 4)/(-2x + 1)] d) lim x → ∞ [(2e^x + 1)/(e^x - 1)]
Sannachikke Gowda .
Find the limit. $$\lim _{x \rightarrow \infty} \frac{3 x+5}{x-4}$$
Limits and Derivatives
Limits Involving Infinity
Find each limit, if possible. (a) $\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 x^{2}+1}$ (b) $\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 x^{3 / 2}+1}$ (c) $\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 \sqrt{x}+1}$
Applications of Differentiation
Limits at Infinity
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD