$dE = K \frac{\mathcal{E}_A}{r} \cos[\omega t - k(\rho + r)] dS$ (10.74)
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First, we need to understand the meaning of each term in the equation. - dE represents the differential amount of electric field energy. - K is a constant that depends on the properties of the medium in which the electric field exists. - A is the amplitude of Show more…
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