Using the combination formula, we have:
$$
^4C_2 = \frac{4!}{2!(4-2)!} = \frac{4!}{2!2!} = \frac{4 \times 3}{2 \times 1} = 6
$$
So, 2C4 = 6.
Now, let's find the value of 2C' 2C2". We can rewrite this as:
$$
^2C_1 \times ^2C_2 = \frac{2!}{1!(2-1)!} \times
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