Question

(d) $h(x) = \ln(\sin x)$ (e) $f(x) = 3 \arctan(e^{2x})$

          (d) $h(x) = \ln(\sin x)$ 
(e) $f(x) = 3 \arctan(e^{2x})$

(d) h(x) = ln(sin x)
(e) f(x) = 3 arctan(e^2x)

Added by Anna M.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Avinash Vishwakarma

Step 1

- The range of h(x) is (-∞, ∞) because ln can take any real value. - The derivative of h(x) is h'(x) = cot(x), which is positive in (0, π/2), so h(x) is increasing in this interval. - Show more…

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(d) h(x) = ln(sin x) (e) f(x) = 3arctan(e^2r)

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