6. $sec\theta - tan\theta = \frac{cos\theta}{sin\theta + 1}$
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We know that $\tan e = \frac{\sin e}{\cos e}$ and $\sec e = \frac{1}{\cos e}$. So, the equation becomes: $\cos e \cdot \frac{\sin e}{\cos e} = \sin e + 1$ Now, simplify the equation: $\sin e = \sin e + 1$ Subtract $\sin e$ from both sides: $0 = 1$ This Show more…
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