'COS x y" + y = sin x +COS x'
Added by Elizabeth W.
Step 1
Then, taking the first and second derivatives: y' = -A SIN x + B COS x y" = -A COS x - B SIN x Substituting these into the homogeneous equation, we get: COS x (-A COS x - B SIN x) + (A COS x + B SIN x) = 0 Simplifying, we get: (A + B) COS x = 0 Since COS x Show more…
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