We have:
h) $2\sec{x}(1+\sin{x}) > 1-\sin{x}$
Now, we know that $\sec{x} = \frac{1}{\cos{x}}$. So, we can rewrite the inequality as:
$2\frac{1}{\cos{x}}(1+\sin{x}) > 1-\sin{x}$
Now, let's multiply both sides of the inequality by $\cos{x}$ to get rid of the
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